---

            OpenFileDialog openFileDialog = new OpenFileDialog();
            if (openFileDialog.ShowDialog() == DialogResult.OK)
            {
                string filePath = openFileDialog.FileName;

                if (File.Exists(filePath))
                {
                    string fileContent = File.ReadAllText(filePath);
                    textBoxContent.Text = fileContent;
                }
                else
                {
                    MessageBox.Show("Фаил не сушествует");
                }
            }