select
ps.id,
ps.name,
ps.brief,
ps.code_1c,
ps.index_scheme
from prod_line.pens_scheme ps
where exists (
select 1
from back_office.report_conformity_pu_bu_detail rd
where rd.report_conformity_pu_bu_id = 97
and rd.account in ('38902', '39002')
and rd.pension_scheme_id = ps.id
)
order by ps.id
limit 5;