---

-- 1. Недорогое жильё (<100)
SELECT 
    id AS room_id,
    home_type AS type,
    price AS cost
FROM Rooms
WHERE price < 100;

-- 2. Только жильё с телевизором
SELECT 
    id,
    price
FROM Rooms
WHERE has_tv = TRUE;

-- 3. Квартиры или дома дороже 150
SELECT 
    id,
    home_type,
    price